| ⇦ | 
| ⇨ |
The resistance of a carbon resistor of colour code Red-Red Green Silver is (in kΩ)
Options
(a) 2200±5%
(b) 2200±10%
(c) 220±10%
(d) 220±5%
Correct Answer:
2200±10%
Explanation:
Given, Colour coding of resistance = Red, Red, Green, Silver
First band value = 2
Second band value = 2
Third band value = 10⁵
Fourth band value = ± 10%
Now, R = 22 × 10⁵ ± 10% Ω
R = 2200 ± 10% kΩ
Related Questions: - Which one of the following bonds produces a solid that reflects light in the visible region
- The time period of a simple pendulum in a lift descending with constant acceleration g is
- A particle moves along a circle of radius 20/π m with constant tangential acceleration
- A nucleus of mass number 220, initially at rest, emits an α-particle. If the Q-value
- If we study the vibration of a pipe open at both ends
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which one of the following bonds produces a solid that reflects light in the visible region
- The time period of a simple pendulum in a lift descending with constant acceleration g is
- A particle moves along a circle of radius 20/π m with constant tangential acceleration
- A nucleus of mass number 220, initially at rest, emits an α-particle. If the Q-value
- If we study the vibration of a pipe open at both ends
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply