| ⇦ |
| ⇨ |
The resistance of a carbon resistor of colour code Red-Red Green Silver is (in kΩ)
Options
(a) 2200±5%
(b) 2200±10%
(c) 220±10%
(d) 220±5%
Correct Answer:
2200±10%
Explanation:
Given, Colour coding of resistance = Red, Red, Green, Silver
First band value = 2
Second band value = 2
Third band value = 10⁵
Fourth band value = ± 10%
Now, R = 22 × 10⁵ ± 10% Ω
R = 2200 ± 10% kΩ
Related Questions: - If the density of earth is doubled keeping its radius constant then acceleration
- The energy of a hydrogen atom in the ground state is – 13.6 eV. The energy of a He⁺ ion
- Which series of hydrogen spectrum corresponds to ultraviolet region?
- Ohm’s law valid
- Two bodies of masses m and 4 m are moving with equal K.E. The ratio of their linear
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If the density of earth is doubled keeping its radius constant then acceleration
- The energy of a hydrogen atom in the ground state is – 13.6 eV. The energy of a He⁺ ion
- Which series of hydrogen spectrum corresponds to ultraviolet region?
- Ohm’s law valid
- Two bodies of masses m and 4 m are moving with equal K.E. The ratio of their linear
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply