A condenser of capacity C is charged to a potential difference of V₁. The plates

⇦

⇨

A condenser of capacity C is charged to a potential difference of V₁. The plates of the condenser are then connected to an ideal inductor of inductance L. The current through the inductor when the potential difference across the condenser to V₂ is

Options

(a) [ C (V₁² – V₂²) / L ]¹/²
(b) [ C (V₁ – V₂)² / L ]¹/²
(c) C (V₁² – V₂²) / L
(d) C (V₁ – V₂) / L

Correct Answer:

[ C (V₁² – V₂²) / L ]¹/²

Explanation:

q = CV₁ cos wt
i = dq/ dt = – ?Cv₁ sin ?t
Also, ?ￂﾲ = 1 / LC and V = V₁ cos ?t
At t = t₁, V = V₂ and i = – ?CV₁ sin ?t₁
cos ?t₁ = V₂ / V₁ (-ve sign gives direction)
Hence, i = V √(C/L) [ 1 – V₂² / V₁²) ]¹/²
= [ C (V₁² – V₂²) / L ]¹/²

Related Questions:

1. A 36 Ω galvanometer is shunted by resistance of 4 Ω. The percentage of the total current
2. For a cubic crystal structure which one of the following relations
3. The young’s modulus of steel is twice that of brass. Two wires of same length
4. Copper has face centered cubic (fcc) lattice with interatomic spacing equal to 2.54Å.
5. Two spherical bodies of mass M and 5 M and radii R and 2 R released in free space

Topics: Electrostatics (146)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends