A condenser of capacity C is charged to a potential difference of V₁. The plates

⇦

⇨

A condenser of capacity C is charged to a potential difference of V₁. The plates of the condenser are then connected to an ideal inductor of inductance L. The current through the inductor when the potential difference across the condenser to V₂ is

Options

(a) [ C (V₁² – V₂²) / L ]¹/²
(b) [ C (V₁ – V₂)² / L ]¹/²
(c) C (V₁² – V₂²) / L
(d) C (V₁ – V₂) / L

Correct Answer:

[ C (V₁² – V₂²) / L ]¹/²

Explanation:

q = CV₁ cos wt
i = dq/ dt = – ?Cv₁ sin ?t
Also, ?ￂﾲ = 1 / LC and V = V₁ cos ?t
At t = t₁, V = V₂ and i = – ?CV₁ sin ?t₁
cos ?t₁ = V₂ / V₁ (-ve sign gives direction)
Hence, i = V √(C/L) [ 1 – V₂² / V₁²) ]¹/²
= [ C (V₁² – V₂²) / L ]¹/²

Related Questions:

1. If doubly ionised lithium atom is hydrogen like with atomic number 3, the wavelength
2. The vector sum of two forces is perpendicular to their vector difference. In that case,
3. Water rises to a height h in capillary tube. If the length of capillary tube above
4. An iron rod of volume 10⁻⁴ m³ and relative permeability 1000 is placed inside a long
5. The input resistance of a silicon transistor is 100 W. Base current is changed

Topics: Electrostatics (146)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends