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The refracting angle of a prism is A and refractive index of the material of the prism is cot (A/2). The angle of minimum deviation is
Options
(a) 180⁰-3 A
(b) 180⁰-2 A
(c) 90⁰- A
(d) 180⁰+2 A
Correct Answer:
180⁰-2 A
Explanation:
Refractive index, μ = sin (A+Dm / 2) / sin (A/2)
cot (A / 2) = sin (A+Dm / 2) / sin (A/2)
cos (A/2) / sin (A/2) = sin (A+Dm / 2) / sin (A/2)
sin [(π/2) – (A/2)] = sin [(A + Dm) / 2]
(π / 2) – (A / 2) = (A / 2) + (Dm / 2)
Dm = π – 2A
Angle of minimum deviation, Dm = 180° – 2A
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Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Young’s modulus of the material of a wire is 18×10¹¹ dyne cm⁻².its value in SI is
- A transverse wave is represented by y = a sin (?t – kx)
- For non-conductors, the energy gap is
- The dimension of 1/2ε₀E², where ε₀ is permittivity of free space and E is electric field
- If doubly ionised lithium atom is hydrogen like with atomic number 3, the wavelength
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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