| ⇦ | 
| ⇨ |
The ratio of longest wavelength corresponding to Lyman and Blamer series in hydrogen spectrum is
Options
(a) 3 / 23
(b) 7 / 29
(c) 9 / 13
(d) 5 / 27
Correct Answer:
5 / 27
Explanation:
For Lyman series (2 → 1)
1/λL = R [1 – 1/2] = 3R/4
For Balmer series (3 → 2)
1/λB = R [1/4 – 1/9] = 5R/36
λL / λB = 4/3R / 36/5R = 4/36 (5/3) = 5/27
Related Questions: - The potential energy of a long spring when stretched by 2 cm is U.
- According to photon theory of light which of the following physical quantities,
- Amout of heat required to raise the temperature of a body through 1 K is called its
- A conductor of length 5 cm is moved parallel to itself with a speed of 2 m/s,
- A body is moving in a vertical circle. The string must remain taut at the highest point
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The potential energy of a long spring when stretched by 2 cm is U.
- According to photon theory of light which of the following physical quantities,
- Amout of heat required to raise the temperature of a body through 1 K is called its
- A conductor of length 5 cm is moved parallel to itself with a speed of 2 m/s,
- A body is moving in a vertical circle. The string must remain taut at the highest point
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply