| ⇦ | 
| ⇨ |
The ratio of longest wavelength corresponding to Lyman and Blamer series in hydrogen spectrum is
Options
(a) 3 / 23
(b) 7 / 29
(c) 9 / 13
(d) 5 / 27
Correct Answer:
5 / 27
Explanation:
For Lyman series (2 → 1)
1/λL = R [1 – 1/2] = 3R/4
For Balmer series (3 → 2)
1/λB = R [1/4 – 1/9] = 5R/36
λL / λB = 4/3R / 36/5R = 4/36 (5/3) = 5/27
Related Questions: - The diameter of the eye ball of a normal eye is about 2.5 cm. The power of the eye
- If seperation between screen and source is increased by 2%. What would be the effect
- The upper half of an inclined plane of inclination θ is perfectly smooth while lower
- Initial angular velocity of a circular disc of mass M is ?￢ﾂﾁ.Then, two small spheres
- When indensity of radiation is increased on a photosensitive plate, then
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The diameter of the eye ball of a normal eye is about 2.5 cm. The power of the eye
- If seperation between screen and source is increased by 2%. What would be the effect
- The upper half of an inclined plane of inclination θ is perfectly smooth while lower
- Initial angular velocity of a circular disc of mass M is ?￢ﾂﾁ.Then, two small spheres
- When indensity of radiation is increased on a photosensitive plate, then
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply