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The potential energy of a simple harmonic oscillator when the particle is half way to its end point is (where E is the total energy)
Options
(a) E/8
(b) E/4
(c) E/2
(d) 2E/3
Correct Answer:
E/4
Explanation:
P.E. = (1/2) mω²y² ⇒ At y = a/2 ⇒ (1/2) (mω²a²/4)
Total energy (E) = P.E. at extreme position = (1/2) mω²a²
P.E. = (1/4).[(1/2) mω²a²] = E/4
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The mean free path of electrons in a metal is 4 x 10⁻⁸ m. The electric field
- In Young’s double slit experiment, the slit seperation is 1 mm and the screen
- The electric resistance of a certain wire of iron is R. If its length and radius
- Find out the e.m.f. produced when the current changes from 0 to 1 A in 10 sec.
- Sound waves travel at 350m/s through a warm air and at 3500 m/s through brass
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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