| ⇦ | 
| ⇨ |
The phase difference between the flux linked with a coil rotating in a uniform magnetic field and induced emf produced in it is
Options
(a) π/2
(b) π/3
(c) (-π/6)
(d) π
Correct Answer:
π/2
Explanation:
The flux ɸ = B.A = |B| |A| cos θ
Also, induced emf, ε = – (dɸ / dt) = (d |B| |A| cos θ) / dt
= – |B| |A| [d cos θ / dt] = |B| |A| sin θ. ω
ε = BA ω cos [θ – (π / 2)]
Related Questions: - When a bullet of mass 10 g and speed 100 ms⁻¹ penetrates up to distance 1 cm
- The ratio of amplitude of magnetic field to the amplitude of electric field for
- A body of weight W newton is at the surface of the earth.
- A thin circular ring of mass M and radius R is rotating in a horizontal plane about
- An elevator car whose floor to ceiling distance is equal to 2.7m starts
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When a bullet of mass 10 g and speed 100 ms⁻¹ penetrates up to distance 1 cm
- The ratio of amplitude of magnetic field to the amplitude of electric field for
- A body of weight W newton is at the surface of the earth.
- A thin circular ring of mass M and radius R is rotating in a horizontal plane about
- An elevator car whose floor to ceiling distance is equal to 2.7m starts
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply