The phase difference between the instantaneous velocity and acceleration of a particle

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The phase difference between the instantaneous velocity and acceleration of a particle executing simple harmonic motion is

Options

(a) π
(b) 0.707π
(c) zero
(d) 0.5π

Correct Answer:

0.5π

Explanation:

Let y = A sin ωt
v_inst = dy/ dt = Aω cos ωt
v_inst = Aω² sin (ωt + π/2)
Acceleration = – Aω² sin ωt = Aω²sin (π + ωt)
ɸ = π/2 = 0.5 π.

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Topics: Oscillations (58)
Subject: Physics (2479)

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