⇦ | ⇨ |
The phase difference between the instantaneous velocity and acceleration of a particle executing simple harmonic motion is
Options
(a) π
(b) 0.707π
(c) zero
(d) 0.5π
Correct Answer:
0.5π
Explanation:
Let y = A sin ωt
vinst = dy/ dt = Aω cos ωt
vinst = Aω² sin (ωt + π/2)
Acceleration = – Aω² sin ωt = Aω²sin (π + ωt)
ɸ = π/2 = 0.5 π.
Related Questions: - A stone is tied to a string of length l and whirled in a vertical circle with the other end
- The charge flowing through a resistance R varies with time t as Q=at-bt²,
- Three cells, each of e.m.f 1.5 V and internal resistance 1 ohm are connected in parallel
- The current flowing through a lamp marked as 50 W and 250 V is
- When two identical capacitors are in series, they have 3 μF capacitance
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A stone is tied to a string of length l and whirled in a vertical circle with the other end
- The charge flowing through a resistance R varies with time t as Q=at-bt²,
- Three cells, each of e.m.f 1.5 V and internal resistance 1 ohm are connected in parallel
- The current flowing through a lamp marked as 50 W and 250 V is
- When two identical capacitors are in series, they have 3 μF capacitance
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply