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The period of oscillation of a mass M suspended from a spring of negligible mass is T. If along with it another mass M is also suspended, the period of oscillation will now be
Options
(a) T
(b) T / √2
(c) 2T
(d) √2T
Correct Answer:
√2T
Explanation:
T = 2π √(m / K)
T₁ / T₂ = √(M₁ /M₂)
T₂ = T₁√(M₂ / M₁) = T₁ √(2M / M)
T₂ = T₁ √2 = √2 T (where T₁ = T)
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Water flows through a pipe. The area of cross-section at one place A₁=10 cm²,
- The volume of a nucleus is directly proportional to
- The voltage of clouds is 4×10⁶ volt with respect to ground. In a lightening
- In potentiometer experiment, a cell of emf 1.25V gives balancing length of 30 cm
- An electric dipole is placed at an angle 30°with an electric field intensity 2×10⁵N/C.
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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