| ⇦ | 
| ⇨ |
The period of oscillation of a mass M suspended from a spring of negligible mass is T. If along with it another mass M is also suspended, the period of oscillation will now be
Options
(a) T
(b) T / √2
(c) 2T
(d) √2T
Correct Answer:
√2T
Explanation:
T = 2π √(m / K)
T₁ / T₂ = √(M₁ /M₂)
T₂ = T₁√(M₂ / M₁) = T₁ √(2M / M)
T₂ = T₁ √2 = √2 T (where T₁ = T)
Related Questions: - An a.c. supply gives 30 volt r.m.s which passes through a 10Ω resistance.
- A wave travelling in the +ve x-direction having displacement along y-direction as 1m
- The S.I. unit of electric flux is
- An electromagnetic wave of frequency v = 3.0 MHz passes from vacuum into
- Fission of nuclei is possible because the binding energy per nucleon in them
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An a.c. supply gives 30 volt r.m.s which passes through a 10Ω resistance.
- A wave travelling in the +ve x-direction having displacement along y-direction as 1m
- The S.I. unit of electric flux is
- An electromagnetic wave of frequency v = 3.0 MHz passes from vacuum into
- Fission of nuclei is possible because the binding energy per nucleon in them
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply