| ⇦ | 
| ⇨ |
The number of gram molecules of oxygen in 6.02 x 10²⁴ CO molecules is
Options
(a) 10 gm molecules
(b) 5 gm molecules
(c) 1 gm molecules
(d) 0.5 gm molecules
Correct Answer:
5 gm molecules
Explanation:
6.02 x 10²³ molecules of CO = 1 mole of CO
6.02 x 10²⁴ molecules of CO = 10 mole of CO
= 10 g atoms of O = 5 g molecules of O₂
Related Questions: - Biuret test is not given by
- In the chemical reaction
2SO₂ + O₂ ⇌ 2SO₃,
increasing the total pressure leads to
- If Avogadro number NA, is charged from 6.022 ˣ 10²³ mol⁻¹ to 6.022 ˣ 10²⁰ mol⁻¹
- The reagent commonly used to determine hardness of water titrimetrically is
- The number of carbon atoms in Buckminsterfullerene is
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Biuret test is not given by
- In the chemical reaction 2SO₂ + O₂ ⇌ 2SO₃, increasing the total pressure leads to
- If Avogadro number NA, is charged from 6.022 ˣ 10²³ mol⁻¹ to 6.022 ˣ 10²⁰ mol⁻¹
- The reagent commonly used to determine hardness of water titrimetrically is
- The number of carbon atoms in Buckminsterfullerene is
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply