| ⇦ | 
| ⇨ |
The momentum of a body is increased by 20%.The percentage increases in kinetic energy is
Options
(a) 54 %
(b) 44 %
(c) 100 %
(d) 50 %
Correct Answer:
44 %
Explanation:
Increase in KE = p²/2m
New momentum = p + p/5 = 6p/5
KE(f) = [(6/5).p]²/2m = (36/25).(p²/2m)
ΔKE = (36/25).(p²/2m) – (p²/2m) = (11p²/252m)
Percentage increase = 44%
Related Questions: - Pick out the statement ehich is incorrect?
- The specific charge of a proton is 9.6×10⁷ C/kg. The specific charge of an alpha particle
- Light from the constellation Virgo is observed to increase in wavelength by 0.4%
- A dip needle vibrates in a vertical plane perpendicular to magnetic meridian. The time
- A sound absorber attenuates the sound level by 20 dB. The intensity decreases
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Pick out the statement ehich is incorrect?
- The specific charge of a proton is 9.6×10⁷ C/kg. The specific charge of an alpha particle
- Light from the constellation Virgo is observed to increase in wavelength by 0.4%
- A dip needle vibrates in a vertical plane perpendicular to magnetic meridian. The time
- A sound absorber attenuates the sound level by 20 dB. The intensity decreases
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply