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The momentum of a body is increased by 20%.The percentage increases in kinetic energy is
Options
(a) 54 %
(b) 44 %
(c) 100 %
(d) 50 %
Correct Answer:
44 %
Explanation:
Increase in KE = p²/2m
New momentum = p + p/5 = 6p/5
KE(f) = [(6/5).p]²/2m = (36/25).(p²/2m)
ΔKE = (36/25).(p²/2m) – (p²/2m) = (11p²/252m)
Percentage increase = 44%
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Question Type: Memory
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two racing cars of masses m₁ and m₂ are moving in circles of radii
- A wire is suspended vertically from one of its ends is stretched by attaching a weight
- Dimensions of Torque are
- Three unequal resistors in parallel are equivalent to a resistance 1 Ω.
- The angular velocity of second’s hand of a watch is
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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