| ⇦ | 
| ⇨ |
The mass of a ⁷₃ Li nucleus is 0.042 u less than the sum of the masses of all its nucleons. The binding energy per nucleon of ⁷₃ Li nucleus is nearly
Options
(a) 46 MeV
(b) 5.6 MeV
(c) 3.9 MeV
(d) 23 MeV
Correct Answer:
5.6 MeV
Explanation:
B.E. = 0.042 x 931 = 42 MeV
Number of nucleons in ⁷₃Li is 7.
B.E. / nucleon = 42/7 = 6 MeV
app. 5.6 MeV
Related Questions: - A circular disc rolls down an inclined plane.The ratio of rotational kinetic energy
- The capacitance of two concentric spherical shells of radii R₁ and R₂ (R₂>R₁) is
- The core of a transformer is laminated because
- Young’s modulus of the material of a wire is 18×10¹¹ dyne cm⁻².its value in SI is
- A bullet loses 1/20 of its velocity after penetrating a plank.How many planks
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A circular disc rolls down an inclined plane.The ratio of rotational kinetic energy
- The capacitance of two concentric spherical shells of radii R₁ and R₂ (R₂>R₁) is
- The core of a transformer is laminated because
- Young’s modulus of the material of a wire is 18×10¹¹ dyne cm⁻².its value in SI is
- A bullet loses 1/20 of its velocity after penetrating a plank.How many planks
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply