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In the Bohr’s model of hydrogen atom, the ratio of the kinetic energy to the total energy of the electron in nth quantum state is
Options
(a) (-1)
(b) (+1)
(c) (-2)
(d) (+2)
Correct Answer:
(-1)
Explanation:
In Bohr’s model of hydrogen atom, the kinetic energy of the electron in nᵗʰ state is given by
K = me⁴ / 8ε₀²h²n² = (13.6 / n²) eV
where, me⁴ / 8ε₀²h² = 13.6 eV
The potential energy of electron in nᵗʰ state is given by
U = -2me⁴ / 8ε₀²h²n² = (-27.2 / n²) eV
Total energy of electron in nᵗʰ state is given by
E = K + U = (me⁴ / 8ε₀²h²n² ) – (2me⁴ / 8ε₀²h²n²)
E = -me⁴ / 8ε₀²h²n² = (-13.6 / n ²) eV
.·. K / E = -1
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Weber/m² is equal to
- For the action of a common Base (CB) transistor, (E=emitter, B= base, C= collector)
- Three capacitors each of capacity 4 μF are to be connected in such a way that the effective
- If 10000 V is applied across an X-ray tube, what will be the ratio of de-Broglie
- If ∆Q>0 when heat flows into a system, ∆W>0 when work is done on the system
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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