In the Bohr’s model of hydrogen atom, the ratio of the kinetic energy to the total

⇦

⇨

In the Bohr’s model of hydrogen atom, the ratio of the kinetic energy to the total energy of the electron in nth quantum state is

Options

(a) (-1)
(b) (+1)
(c) (-2)
(d) (+2)

Correct Answer:

(-1)

Explanation:

In Bohr’s model of hydrogen atom, the kinetic energy of the electron in nᵗʰ state is given by
K = me⁴ / 8ε₀²h²n² = (13.6 / n²) eV
where, me⁴ / 8ε₀²h² = 13.6 eV
The potential energy of electron in nᵗʰ state is given by
U = -2me⁴ / 8ε₀²h²n² = (-27.2 / n²) eV
Total energy of electron in nᵗʰ state is given by
E = K + U = (me⁴ / 8ε₀²h²n² ) – (2me⁴ / 8ε₀²h²n²)
E = -me⁴ / 8ε₀²h²n² = (-13.6 / n ²) eV
.·. K / E = -1

Related Questions:

1. The self-inductance of a coil having 500 turns is 50mH. The magnetic flux
2. A uniform chain of length L and mass m is kept on a smooth table. It is released
3. The velocity of molecules of a gas at temperature 120 K is v. At what temperature
4. when a magnetic field is applied on a stationary electron, then it
5. A 1 kg particle strikes a wall with velocity 1 m/s at an angle 30° and reflects

Topics: Atoms and Nuclei (136)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends