| ⇦ | 
| ⇨ |
The mass of a ⁷₃ Li nucleus is 0.042 u less than the sum of the masses of all its nucleons. The binding energy per nucleon of ⁷₃ Li nucleus is nearly
Options
(a) 46 MeV
(b) 5.6 MeV
(c) 3.9 MeV
(d) 23 MeV
Correct Answer:
5.6 MeV
Explanation:
B.E. = 0.042 x 931 = 42 MeV
Number of nucleons in ⁷₃Li is 7.
B.E. / nucleon = 42/7 = 6 MeV
app. 5.6 MeV
Related Questions: - What is the energy released by fission of 1 g of U²³⁵?
- The periodic waves of intensities I₁ and I₂ pass through a region at the same time
- Across a metallic conductor of non-uniform cross-section, a constant potential
- Dimensions of resistance in an electrical circuit, in terms of dimension of mass M,
- In radioactive element, β-rays are emitted from
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- What is the energy released by fission of 1 g of U²³⁵?
- The periodic waves of intensities I₁ and I₂ pass through a region at the same time
- Across a metallic conductor of non-uniform cross-section, a constant potential
- Dimensions of resistance in an electrical circuit, in terms of dimension of mass M,
- In radioactive element, β-rays are emitted from
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply