| ⇦ | 
| ⇨ |
If the self inductance of 500 turn coil is 125 mH, then the self inductance of similar coil of 800 turns is
Options
(a) 48.4 mH
(b) 200 mH
(c) 187.5 mH
(d) 320 mH
Correct Answer:
320 mH
Explanation:
Self inductance of a coil, L = μᵣμ₀n² Al
Where μᵣ is the relative permittivity of the coil, n is the number of terms per unit length, A is the area of cross-section, l is the length of the solenoid
L ∝ n²
Self inductance of 500 turns coil = 125 mH Therefore, L for the coil of 800 turns = [125 / (500)²] × 800² L = 320 mH
Related Questions: - An electric dipole of moment ‘p’ is placed in an elecatric field of intensity ‘E’
- In N-type semi-conductor current is due to
- A nucleus of uranium decays at rest into nuclei of thrrium and helium. Then
- A particle of mass M is suited at the centre of a spherical shell of same mass and radius
- In a transistor the collector current is always less than the emitter current
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An electric dipole of moment ‘p’ is placed in an elecatric field of intensity ‘E’
- In N-type semi-conductor current is due to
- A nucleus of uranium decays at rest into nuclei of thrrium and helium. Then
- A particle of mass M is suited at the centre of a spherical shell of same mass and radius
- In a transistor the collector current is always less than the emitter current
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply