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The energy of a hydrogen atom in the ground state is -13.6 eV. The energy of a He⁺ ion in the first excited state will be
Options
(a) – 13.6 eV
(b) – 27.7 eV
(c) – 54.4 eV
(d) – 6.8 eV
Correct Answer:
– 13.6 eV
Explanation:
energy of a H-like atom in its nth state is given by
E = – Z² x 13.6 / n² eV
For, first excited state of He⁺, n= 2, Z= 2
Eₕₑ⁺ = – 4/2² x 13.6 = – 13.6 eV
Related Questions: - The energy released in the fission of 1 kg of ₉₂U²³⁵ is (energy per fission = 200 MeV)
- A sample of radioactive element has a mass of 10 gram at an instant t=0.
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The energy released in the fission of 1 kg of ₉₂U²³⁵ is (energy per fission = 200 MeV)
- A sample of radioactive element has a mass of 10 gram at an instant t=0.
- A body of mass m slides down an incline and reaches the bottom
- A ray enters a glass sphere of refractive index μ=√3 at an angle of incidence of 60⁰
- Which of the following atoms has the lowest ionisation potential?
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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