The kinetic energy of an electron in the first excited state is

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The total energy of electron in the ground state of hydrogen atom is -13.6 eV. The kinetic energy of an electron in the first excited state is

Options

(a) 6.8 eV
(b) 13.6 eV
(c) 1.7 eV
(d) 3.4 eV

Correct Answer:

3.4 eV

Explanation:

Energy in the first excited state
= – 13.6 / n² = – 13.6 / 2² = – 3.4 eV
But K.E. = – (Total energy) = +3.4 eV.

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Topics: Atoms and Nuclei (136)
Subject: Physics (2479)

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