The kinetic energy of an electron in the first excited state is

The Total Energy Of Electron In The Ground State Of Physics Question

The total energy of electron in the ground state of hydrogen atom is -13.6 eV. The kinetic energy of an electron in the first excited state is

Options

(a) 6.8 eV
(b) 13.6 eV
(c) 1.7 eV
(d) 3.4 eV

Correct Answer:

3.4 eV

Explanation:

Energy in the first excited state
= – 13.6 / n² = – 13.6 / 2² = – 3.4 eV
But K.E. = – (Total energy) = +3.4 eV.

Related Questions:

  1. Out of the following options which one can be used to produce a propagating
  2. If the sodium light in Young’s double slit experiment is replaced by red light
  3. The ratio of amplitude of magnetic field to the amplitude of electric field for
  4. When a string is divided into three segments of length l₁, l₂ and l₃ the fundamental
  5. A stone falls freely under gravity.It covers distances h₁,h₂ and h₃

Topics: Atoms and Nuclei (136)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*