| ⇦ |
| ⇨ |
An A.C source is rated at 220 V, 50 Hz. The time taken for voltage to change from its peak value to zero is
Options
(a) 50 sec
(b) 0.02 sec
(c) 5 sec
(d) 5 x 10⁻³ sec
Correct Answer:
5 x 10⁻³ sec
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The value of Planck’s constant is
- When the length of the vibrating segment of a sonometer wire is increased by
- Three masses are placed on the x-axis : 300 g at origin, 500 g at x = 40 cm
- A rectangular coil of length 0.12 m and width 0.1 m having 50 turns of wire
- A particle moves in xy plane according to the equation x = 4t² + 5t + 16 and y = 5t
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The value of Planck’s constant is
- When the length of the vibrating segment of a sonometer wire is increased by
- Three masses are placed on the x-axis : 300 g at origin, 500 g at x = 40 cm
- A rectangular coil of length 0.12 m and width 0.1 m having 50 turns of wire
- A particle moves in xy plane according to the equation x = 4t² + 5t + 16 and y = 5t
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply