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The total energy of electron in the ground state of hydrogen atom is -13.6 eV. The kinetic energy of an electron in the first excited state is
Options
(a) 6.8 eV
(b) 13.6 eV
(c) 1.7 eV
(d) 3.4 eV
Correct Answer:
3.4 eV
Explanation:
Energy in the first excited state
= – 13.6 / n² = – 13.6 / 2² = – 3.4 eV
But K.E. = – (Total energy) = +3.4 eV.
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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