| ⇦ |
| ⇨ |
The total energy of electron in the ground state of hydrogen atom is -13.6 eV. The kinetic energy of an electron in the first excited state is
Options
(a) 6.8 eV
(b) 13.6 eV
(c) 1.7 eV
(d) 3.4 eV
Correct Answer:
3.4 eV
Explanation:
Energy in the first excited state
= – 13.6 / n² = – 13.6 / 2² = – 3.4 eV
But K.E. = – (Total energy) = +3.4 eV.
Related Questions: - An aicraft executes a horizontal loop of radius 1 km with a speed of 900 kmh⁻¹
- If ₉₂U²³⁸ undergoes successively 8 ∝-decays and 6 β-decays, the resulting nucleus is
- A student measures the terminal potential difference (V) of a cell
- Two charges each equal to 2µ C are 0.5m apart. If both of them exist inside vacuum
- A parallel plate condenser has a uniform electric field E(V/m) in the space between
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An aicraft executes a horizontal loop of radius 1 km with a speed of 900 kmh⁻¹
- If ₉₂U²³⁸ undergoes successively 8 ∝-decays and 6 β-decays, the resulting nucleus is
- A student measures the terminal potential difference (V) of a cell
- Two charges each equal to 2µ C are 0.5m apart. If both of them exist inside vacuum
- A parallel plate condenser has a uniform electric field E(V/m) in the space between
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply