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The induced emf in a coil of 10 H inductance in which current varies from 9 A to 4 A in 0.2 s is
Options
(a) 200 V
(b) 250 V
(c) 300 V
(d) 350 V
Correct Answer:
250 V
Explanation:
Induced emf, e = -L (di / dt)
Given, L = 10 H, Δi = 9 – 4 = 5 A,
dt = 0.2 s
emf, e = 10 × (5 / 0.2) = 250 V
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Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An aeroplane flies 400m due to North and then 300m due to south and then flies
- Two bodies of mass 1 kg and 3 kg have positive vectors i + 2j + k and -3i -2j + k
- A conducting sphere of radius R is given a charge Q. The electric potential
- Two beams of light having intensities I and 4I interfere to produce a fringe pattern
- What is the time taken by moon light to reach earth?
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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