| ⇦ | 
| ⇨ |
The induced emf in a coil of 10 H inductance in which current varies from 9 A to 4 A in 0.2 s is
Options
(a) 200 V
(b) 250 V
(c) 300 V
(d) 350 V
Correct Answer:
250 V
Explanation:
Induced emf, e = -L (di / dt)
Given, L = 10 H, Δi = 9 – 4 = 5 A,
dt = 0.2 s
emf, e = 10 × (5 / 0.2) = 250 V
Related Questions: - An ideal coil of 10 H is connected in series with a resistance of 5Ω and a battery
- The drift speed of electrons in copper wire of diameter and length l is v.
- Imagine a light planet revolving around a very massive star in a circular
- If the rise in height of capillary of two tubes is 6.6 cm and 2.2 cm
- A coil of 100 turns carries a current of 5 mA and creates a magnetic flux of 10⁻⁵ Wb.
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An ideal coil of 10 H is connected in series with a resistance of 5Ω and a battery
- The drift speed of electrons in copper wire of diameter and length l is v.
- Imagine a light planet revolving around a very massive star in a circular
- If the rise in height of capillary of two tubes is 6.6 cm and 2.2 cm
- A coil of 100 turns carries a current of 5 mA and creates a magnetic flux of 10⁻⁵ Wb.
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply