⇦ | ⇨ |
The induced emf in a coil of 10 H inductance in which current varies from 9 A to 4 A in 0.2 s is
Options
(a) 200 V
(b) 250 V
(c) 300 V
(d) 350 V
Correct Answer:
250 V
Explanation:
Induced emf, e = -L (di / dt)
Given, L = 10 H, Δi = 9 – 4 = 5 A,
dt = 0.2 s
emf, e = 10 × (5 / 0.2) = 250 V
Related Questions: - A current is flowing through resistance. A potential difference of 120 V
- ₉₂U²³⁵ undergoes successive disintegrations with the end product of ₈₂P²⁰³
- A particle doing SHM has amplitude=4 cm and time period = 12 sec. The ratio between times
- A carnot’s engine operates with source at 127° C and sink at 27°C
- Two identical circular coils A and B are kept on a horizontal tube
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A current is flowing through resistance. A potential difference of 120 V
- ₉₂U²³⁵ undergoes successive disintegrations with the end product of ₈₂P²⁰³
- A particle doing SHM has amplitude=4 cm and time period = 12 sec. The ratio between times
- A carnot’s engine operates with source at 127° C and sink at 27°C
- Two identical circular coils A and B are kept on a horizontal tube
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply