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The induced emf in a coil of 10 H inductance in which current varies from 9 A to 4 A in 0.2 s is
Options
(a) 200 V
(b) 250 V
(c) 300 V
(d) 350 V
Correct Answer:
250 V
Explanation:
Induced emf, e = -L (di / dt)
Given, L = 10 H, Δi = 9 – 4 = 5 A,
dt = 0.2 s
emf, e = 10 × (5 / 0.2) = 250 V
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Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The string of a pendulum is horizontal.The mass of bob attached to it is m
- Photons of 5.5 eV energy fall on the surface of the metal emitting photoelectrons
- α-particles, deuterons and protons of same energy are moving in a perpendicular
- In a region, the potential is represented by V(x,y,z)=6x-8xy-8y+6yz, where V
- A particle has initial velocity (3i + 4j) and acceleration (0.1 i+0.3j). It’s speed after 10s
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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