| ⇦ | 
| ⇨ |
If a charge in current of 0.01 A in one coil produces a change in magnetic flux of 1.2 x 10⁻² Wb in the outer coil, then the mutual inductance of the coils in henry is
Options
(a) 0
(b) 1.2
(c) 3
(d) 1.5
Correct Answer:
1.2
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - In photoelectric effect, the photoelectric current
- A bar magnet of moment M and pole strength m is cut into parts of equal lengths.
- What is the difference between soft and hard X-ray?
- A slab consists of two parallel layers of two different materials of same thickness
- A particle is dropped vertically from rest, from a height.The time taken by it to fall
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In photoelectric effect, the photoelectric current
- A bar magnet of moment M and pole strength m is cut into parts of equal lengths.
- What is the difference between soft and hard X-ray?
- A slab consists of two parallel layers of two different materials of same thickness
- A particle is dropped vertically from rest, from a height.The time taken by it to fall
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Magenetic flux=LXdI/dt
flux=2 x 10^(-2)
current flown in 1 sec is 0.001 amppere
ie,dI/dt = 0.01A
=>2 x 10^(-2) = L x 0.001
=>L = 2 x 10^(-2)/0.001
=>L = 2H