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The induced emf in a coil of 10 H inductance in which current varies from 9 A to 4 A in 0.2 s is
Options
(a) 200 V
(b) 250 V
(c) 300 V
(d) 350 V
Correct Answer:
250 V
Explanation:
Induced emf, e = -L (di / dt)
Given, L = 10 H, Δi = 9 – 4 = 5 A,
dt = 0.2 s
emf, e = 10 × (5 / 0.2) = 250 V
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¹H+⁷Li→⁴He+⁴He
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Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- What is the Q-value of the reaction? ¹H+⁷Li→⁴He+⁴He
- A charged particle enters a uniform magnetic field with a certain speed at right angles
- Two slits in Young’s experiment have widths in the ratio 1:25. The ratio of intensity
- Two wires of equal length and equal diameter and having resistivities ρ₁ and ρ₂
- A uniform chain of length L and mass m is kept on a smooth table. It is released
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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