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The induced emf in a coil of 10 H inductance in which current varies from 9 A to 4 A in 0.2 s is
Options
(a) 200 V
(b) 250 V
(c) 300 V
(d) 350 V
Correct Answer:
250 V
Explanation:
Induced emf, e = -L (di / dt)
Given, L = 10 H, Δi = 9 – 4 = 5 A,
dt = 0.2 s
emf, e = 10 × (5 / 0.2) = 250 V
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Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A spring of spring constant 5 x 10³ N/m is stretched initially by 5 cm
- A wire of a certain material is stretched slowly by ten percent. Its new resistance
- The displacement of particle is given by x=aₒ+(a₁t/2)-(a₂t²/3) what is acceleration?
- The potential energy of a long spring when stretched by 2 cm is U.
- An unpolarised beam of intensity I is incident on a pair of nicols making an angle
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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