| ⇦ | 
| ⇨ |
The horizontal and vertical components of earth’s magnetic field at a place are 0.3 G and 0.52 G. The earth’s magnetic field and the angle of dip are
Options
(a) 0.3 G and δ=30⁰
(b) 0.4 G and δ=40⁰
(c) 0.5 G and δ=50⁰
(d) 0.6 G and δ=60⁰
Correct Answer:
0.6 G and δ=60⁰
Explanation:
As, Bᴇ = √(Bʜ² + Bv²) and tan δ = Bv / Bʜ
Given, Bʜ = 0.3 G, Bv = 0.52 G
Bᴇ = √[(0.3)² + (0.52)²] = √0.36 = 0.6 G and δ = tan⁻¹ (Bv / Bʜ) = tan⁻¹ (0.52 / 0.3) = 60°
Related Questions: - Oil spreads over the surface of water where as water does not spread
- The mass number of nucleus is always
- 180⁰ phase difference is obtained when light ray is reflected from
- A small angled prism of refractive index 1.4 is combined with another small angled prism
- A wire in the form of a circular loop of one turn, carrying a current, produces
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Oil spreads over the surface of water where as water does not spread
- The mass number of nucleus is always
- 180⁰ phase difference is obtained when light ray is reflected from
- A small angled prism of refractive index 1.4 is combined with another small angled prism
- A wire in the form of a circular loop of one turn, carrying a current, produces
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply