| ⇦ | 
| ⇨ |
The horizontal and vertical components of earth’s magnetic field at a place are 0.3 G and 0.52 G. The earth’s magnetic field and the angle of dip are
Options
(a) 0.3 G and δ=30⁰
(b) 0.4 G and δ=40⁰
(c) 0.5 G and δ=50⁰
(d) 0.6 G and δ=60⁰
Correct Answer:
0.6 G and δ=60⁰
Explanation:
As, Bᴇ = √(Bʜ² + Bv²) and tan δ = Bv / Bʜ
Given, Bʜ = 0.3 G, Bv = 0.52 G
Bᴇ = √[(0.3)² + (0.52)²] = √0.36 = 0.6 G and δ = tan⁻¹ (Bv / Bʜ) = tan⁻¹ (0.52 / 0.3) = 60°
Related Questions: - Ist law of thermadynamics is based on
- Two lines of force due to a bar magnet
- A charged particle enters a uniform magnetic field with a certain speed at right angles
- An ideal spring with spring constant K is hung from the ceiling and a block of mass
- If the binding energy of the nucleon in ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06 MeV
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Ist law of thermadynamics is based on
- Two lines of force due to a bar magnet
- A charged particle enters a uniform magnetic field with a certain speed at right angles
- An ideal spring with spring constant K is hung from the ceiling and a block of mass
- If the binding energy of the nucleon in ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06 MeV
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply