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The horizontal and vertical components of earth’s magnetic field at a place are 0.3 G and 0.52 G. The earth’s magnetic field and the angle of dip are
Options
(a) 0.3 G and δ=30⁰
(b) 0.4 G and δ=40⁰
(c) 0.5 G and δ=50⁰
(d) 0.6 G and δ=60⁰
Correct Answer:
0.6 G and δ=60⁰
Explanation:
As, Bᴇ = √(Bʜ² + Bv²) and tan δ = Bv / Bʜ
Given, Bʜ = 0.3 G, Bv = 0.52 G
Bᴇ = √[(0.3)² + (0.52)²] = √0.36 = 0.6 G and δ = tan⁻¹ (Bv / Bʜ) = tan⁻¹ (0.52 / 0.3) = 60°
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Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A spherical drop of mercury having a potential of 2.5 v is obtained as a result
- On the horizontal surface of a truck a block of mass 1 kg is placed (µ=0.6) and truck
- A small block of super dense material has mass 3 x 10²⁴ kg.It is situated at a height
- The dimensions of universal gas constant are
- Dependence of intensity of gravitational field (E) of earth with distance(r)
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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