| ⇦ |
| ⇨ |
The dimensions of universal gas constant are
Options
(a) [ML²T⁻²θ⁻¹]
(b) [M²LT⁻²θ]
(c) [ML³T⁻²θ⁻¹]
(d) None of these
Correct Answer:
[ML²T⁻²θ⁻¹]
Explanation:
According to Ideal gas equation, PV = nRT
where P is the pressure, V is the volume, n is the no of moles, R is gas constant and T is temperature.
now , R = PV/nT
dimension of pressure = [ML⁻¹T⁻²]
dimension of volume = [ L³ ]
dimension of mole = no dimension
dimension of temperature = [ θ]
So , dimension of R =[ML⁻¹T⁻²][L³]/[θ]
=[ ML²T⁻²θ⁻¹]
Related Questions: - A body of mass 120 kg and density 600 kg/m³ floats in water.
- The mean free path of electrons in a metal is 4 x 10⁻⁸ m. The electric field
- An object is placed at a distance of 10 cm from a co-axial combination of two lenses
- Three blocks A,B and C of masses 4 kg, 2 kg and 1 kg respectively are in contact
- If a carnot engine is working with source temperature at 227⁰C and sink
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Physical World and Measurement
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body of mass 120 kg and density 600 kg/m³ floats in water.
- The mean free path of electrons in a metal is 4 x 10⁻⁸ m. The electric field
- An object is placed at a distance of 10 cm from a co-axial combination of two lenses
- Three blocks A,B and C of masses 4 kg, 2 kg and 1 kg respectively are in contact
- If a carnot engine is working with source temperature at 227⁰C and sink
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Physical World and Measurement (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply