| ⇦ | 
| ⇨ |
The frequency of a light wave in a material is 2 x 10¹⁴ Hz and wavelength is 5000Å. The refractive index of material will be
Options
(a) 1.5
(b) 3
(c) 1.33
(d) 1.4
Correct Answer:
3
Explanation:
By using v = nλ , n = 2 x 10¹⁴ Hz
λ = 5000Å = 5000 x 10⁻¹⁰ m
v = 2 x 10¹⁴ x 5000 x 10⁻¹⁰ = 10⁸ m/s
Refractive index of the material,
µ = c / v = 3 x 10⁸ / 10⁸ = 3
Related Questions: - A body of mass 2 kg is kept by pressing to a vertical wall by a force of 100 N
- Thomson coefficient of a conductor is 10 µV/K. Its two ends are kept
- A proton and an alpha particle both enter a region of uniform magnetic field B,
- The ionisation energy of hydrogen is 13.6 eV. The energy of the photon released
- Diameter of the objective of a telescope is 200 cm. What is the resolving power
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body of mass 2 kg is kept by pressing to a vertical wall by a force of 100 N
- Thomson coefficient of a conductor is 10 µV/K. Its two ends are kept
- A proton and an alpha particle both enter a region of uniform magnetic field B,
- The ionisation energy of hydrogen is 13.6 eV. The energy of the photon released
- Diameter of the objective of a telescope is 200 cm. What is the resolving power
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply