| ⇦ | 
| ⇨ |
The frequency of a light wave in a material is 2 x 10¹⁴ Hz and wavelength is 5000Å. The refractive index of material will be
Options
(a) 1.5
(b) 3
(c) 1.33
(d) 1.4
Correct Answer:
3
Explanation:
By using v = nλ , n = 2 x 10¹⁴ Hz
λ = 5000Å = 5000 x 10⁻¹⁰ m
v = 2 x 10¹⁴ x 5000 x 10⁻¹⁰ = 10⁸ m/s
Refractive index of the material,
µ = c / v = 3 x 10⁸ / 10⁸ = 3
Related Questions: - In a radioactive decay process, the negatively charged emitted β- particles are
- Application of Bernoulli’s theorem can be seen in
- A parallel plate condenser with a dielectric of dielectric constant K between the plates
- In Young’s double slit experiment, a third slit is made in between the double slits.
- Two bullets are fired simultaneously, horizontally and with different speeds
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In a radioactive decay process, the negatively charged emitted β- particles are
- Application of Bernoulli’s theorem can be seen in
- A parallel plate condenser with a dielectric of dielectric constant K between the plates
- In Young’s double slit experiment, a third slit is made in between the double slits.
- Two bullets are fired simultaneously, horizontally and with different speeds
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply