| ⇦ | 
| ⇨ |
The weight of a body on surface of earth is 12.6 N. When it is raised to a height half the radius of earth its weight will be
Options
(a) 2.8 N
(b) 5.6 N
(c) 12.6 N
(d) 25.2 N
Correct Answer:
5.6 N
Explanation:
Weight of body on the surface of earth, mg=12.6 N
At height h, the value of g’ is given by
g’=g (R/R+(R/2))²
=g 4/9
Weight at height, h=mg 4/9
h=12.6×4/9 =5.6 N
Related Questions: - ln a surrounding medium of temperature 10⁰C a body takes 7 min for a fall
- Electron in hydrogen atom first jumps from third excited state to second excited
- A coil of resistance 10 Ω and an inductance 5 H is connected to a 100 volt
- The product of pressure and volume hve thesame units as the product of
- Two simple harmonic motions of angular frequency 100 and 1000 rad s⁻¹ have the same
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- ln a surrounding medium of temperature 10⁰C a body takes 7 min for a fall
- Electron in hydrogen atom first jumps from third excited state to second excited
- A coil of resistance 10 Ω and an inductance 5 H is connected to a 100 volt
- The product of pressure and volume hve thesame units as the product of
- Two simple harmonic motions of angular frequency 100 and 1000 rad s⁻¹ have the same
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply