When ₃Li⁷ nuclei are bombarded by protons, and the resultant nuclei are ₄Be⁸,

When Li Nuclei Are Bombarded By Protons And The Resultant Physics Question

When ₃Li⁷ nuclei are bombarded by protons, and the resultant nuclei are ₄Be⁸, the emitted particles will be

Options

(a) neutrons
(b) alpha particles
(c) beta particles
(d) gamma photons

Correct Answer:

gamma photons

Explanation:

₃Li⁷ + ₁H¹ → ₂Be⁴ + zX ᴬ
Z for the unknown X nucleus = 3 + 1 – 4 = 0
A for the unknown X nucleus = 7 + 1 – 8 = 0
Hence particle emitted has zero Z and zero A
It is a gamma photon.

Related Questions:

  1. Complete the reaction: ₀n¹+ ₉₂U²³⁵→₅₆Ba¹⁴⁴+……..+3n
  2. Carbon,silicon and germanium have four valence electrons each. At room temperature
  3. Which of the following is true for elastic potential energy density?
  4. In R-L-C series circuit, the potential differences across each element is 20 V.
  5. The wetability of a surface by a liquid depends primarily on

Topics: Atoms and Nuclei (136)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*