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A light whose frequency is equal to 6.0 x 10¹⁴ Hz is incident on a metal whose work function is 2 eV. (h= 6.63 x 10⁻³⁴ Js, 1 ev = 1.6 x 10⁻¹⁹ J). The maximum energy of the electron emitted will be
Options
(a) 2.49 eV
(b) 4.49 eV
(c) 0.49 eV
(d) 5.49 eV
Correct Answer:
0.49 eV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body of weight W newton is at the surface of the earth.
- If an electron in a hydrogen atom jumps from the 3rd orbit to the 2nd orbit, it emits
- The current in a conductor varies with time t as I=2t+3t² Where I is in amperes
- The effective length of magnet is 31.4 cm and its pole strength is 0.8Am.
- To get three images of single object, one should have two plane mirrors at an angle of
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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