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The excitation potential of hydrogen atom in the first excited state is
Options
(a) 13.6 V
(b) (-13.6 V)
(c) 10.2 V
(d) (-10 V)
Correct Answer:
10.2 V
Explanation:
Energy of electron in ground state of hydrogen atom,
E₁ = -1.36 eV [E(n) = (-13.6 / n²) eV]
Energy of electron in first excited state of hydrogen atom,
E₂ = -13.6 / 2² = – 3.4 eV
Hence, the excitation energy of hydrogen atom in first excited state,
E = E₂ – E₁ = – 3.4 – (-13.6) = 10.2 eV
Therefore, excitation potential is 10.2 V.
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The wavelength of first line of Balmer series is 6563Å. The wavelength of first line
- The ratio of speed of an electron in ground state in Bohr’s first orbit of hydrogen atom
- A plane polarised light is incident normally on a tourmaline plate. Its E vector make
- The moment of inertia of a semicircular ring about the centre is
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Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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