| ⇦ | 
| ⇨ |
The excitation potential of hydrogen atom in the first excited state is
Options
(a) 13.6 V
(b) (-13.6 V)
(c) 10.2 V
(d) (-10 V)
Correct Answer:
10.2 V
Explanation:
Energy of electron in ground state of hydrogen atom,
E₁ = -1.36 eV [E(n) = (-13.6 / n²) eV]
Energy of electron in first excited state of hydrogen atom,
E₂ = -13.6 / 2² = – 3.4 eV
Hence, the excitation energy of hydrogen atom in first excited state,
E = E₂ – E₁ = – 3.4 – (-13.6) = 10.2 eV
Therefore, excitation potential is 10.2 V.
Related Questions: - If rope of lift breaks suddenly, the tension exerted by the surface of the lift
- The value of Planck’s constant is
- A string in musical instrument is 50 cm long and its fundamental frequency is 800 Hz.
- The temperature of a metal block is increased from 27⁰C to 84⁰C. The rate of radiated energy
- By the succesive disintegration of ₉₂U²³⁸, the final product obtained is ₈₂Pb²⁰⁶, then
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If rope of lift breaks suddenly, the tension exerted by the surface of the lift
- The value of Planck’s constant is
- A string in musical instrument is 50 cm long and its fundamental frequency is 800 Hz.
- The temperature of a metal block is increased from 27⁰C to 84⁰C. The rate of radiated energy
- By the succesive disintegration of ₉₂U²³⁸, the final product obtained is ₈₂Pb²⁰⁶, then
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply