| ⇦ | 
| ⇨ |
The energy of a hydrogen atom in the ground state is -13.6 eV. The energy of a He⁺ ion in the first excited state will be
Options
(a) – 13.6 eV
(b) – 27.7 eV
(c) – 54.4 eV
(d) – 6.8 eV
Correct Answer:
– 13.6 eV
Explanation:
energy of a H-like atom in its nth state is given by
E = – Z² x 13.6 / n² eV
For, first excited state of He⁺, n= 2, Z= 2
Eₕₑ⁺ = – 4/2² x 13.6 = – 13.6 eV
Related Questions: - A student performs an experiment to determine the Young’s modulus of a wire
- A stone tied to the end of a string of 1 m long is whirled in a horizontal circle
- Parsec is the unit of
- An electric dipole of moment ‘p’ is placed in an elecatric field of intensity ‘E’
- A 0.01 H inductor and √3 πΩ resistance are connected in series
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A student performs an experiment to determine the Young’s modulus of a wire
- A stone tied to the end of a string of 1 m long is whirled in a horizontal circle
- Parsec is the unit of
- An electric dipole of moment ‘p’ is placed in an elecatric field of intensity ‘E’
- A 0.01 H inductor and √3 πΩ resistance are connected in series
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply