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The electric potential at the surface of an atomic nucleus (z=50) of radius 9.0×10⁻¹³ cm is
Options
(a) 80 volt
(b) 8×10⁶ volt
(c) 9 volt
(d) 9×10⁵ volt
Correct Answer:
8×10⁶ volt
Explanation:
V = (1 / 4πε₀). q/r
= [9 × 10⁹ × 50 × 1.6 × 10⁻¹⁹] / 9 × 10⁻¹⁵
= 8 × 10⁶ volt
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Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A thermally insulated rigid container contains an ideal gas heated by a filament
- Sodium has body centred packing. Distance between two nearest atoms is 3.7 Å.
- A cricketer catches a ball of mass 150 g in 0.1 sec moving with speed 20 m/s
- A circular disc of radius 0.2 meter is placed in a uniform magnetic field of induction
- A road of width 20 m forms an arc of radius 15 m,its outer edge is 2m higher than
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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