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The intensity at the maximum in a Young’s double slit experiment is I₀. Distance between two slits is d=5λ, where λ is the wavelength of light used in the experiment. What will be the intensity in front of one of the slits on the screen placed at a distance, D= 10 d?
Options
(a) I₀/4
(b) 3/4 I₀
(c) I₀/2
(d) I₀
Correct Answer:
I₀/2
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle with total energy E is moving in a potential energy region U(x)
- Three resistances 2Ω, 3Ω and 4Ω are connected in parallel. The ratio of currents passing
- If v is the speed of sound in air, then the shortest length of the closed pipe
- A particle is executing the motion x=Acos (ωt-θ). The maximum velocity of the particle is
- When a current of (2.5±0.5) A flows through a wire, it develops a potential difference
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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