| ⇦ | 
| ⇨ |
The intensity at the maximum in a Young’s double slit experiment is I₀. Distance between two slits is d=5λ, where λ is the wavelength of light used in the experiment. What will be the intensity in front of one of the slits on the screen placed at a distance, D= 10 d?
Options
(a) I₀/4
(b) 3/4 I₀
(c) I₀/2
(d) I₀
Correct Answer:
I₀/2
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A rectangular copper coil is placed in a uniform magnetic field of induction 40 mT
- Rutherford’s α-scattering experiment concludes that
- If sound wave travel from air to water, which of the following remains unchanged?
- The potential of a large liquid drop when eight liquid drops are combined is 20 V.
- Two cities are 150 km apart. Electric power is sent from one city to another city
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A rectangular copper coil is placed in a uniform magnetic field of induction 40 mT
- Rutherford’s α-scattering experiment concludes that
- If sound wave travel from air to water, which of the following remains unchanged?
- The potential of a large liquid drop when eight liquid drops are combined is 20 V.
- Two cities are 150 km apart. Electric power is sent from one city to another city
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply