| ⇦ | 
| ⇨ |
The displacement ‘x’ (in meter) of a particle of mass ‘m’ (in kg) moving in one dimension under the action of a force, is related to time ‘t’ (in sec) by t = √x + 3. The displacement of the particle when its velocity is zero, will be
Options
(a) 2 m
(b) 4 m
(c) zero
(d) 6 m
Correct Answer:
zero
Explanation:
t = √x + 3
⇒ √x = t – 3 ⇒ x = (t – 3)²
v = dx/ dt = 2 (t – 3) = 0 ⇒ t = 3
x = (3 – 3)² ⇒ x = 0.
Related Questions: - A black hole is an object whose gravitational field is so strong that even light
- The voltage gain of an amplifier with 9% negative feedback is 10. The voltage gain
- A pan is suspended from a steel wire. Weights are slowly put on the pan
- When a beam of light is used to determine the position of an object,
- A block of mass 0.50 kg is moving with a speed of 2.00 ms⁻¹ on a smooth surface.
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A black hole is an object whose gravitational field is so strong that even light
- The voltage gain of an amplifier with 9% negative feedback is 10. The voltage gain
- A pan is suspended from a steel wire. Weights are slowly put on the pan
- When a beam of light is used to determine the position of an object,
- A block of mass 0.50 kg is moving with a speed of 2.00 ms⁻¹ on a smooth surface.
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply