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The displacement ‘x’ (in meter) of a particle of mass ‘m’ (in kg) moving in one dimension under the action of a force, is related to time ‘t’ (in sec) by t = √x + 3. The displacement of the particle when its velocity is zero, will be
Options
(a) 2 m
(b) 4 m
(c) zero
(d) 6 m
Correct Answer:
zero
Explanation:
t = √x + 3
⇒ √x = t – 3 ⇒ x = (t – 3)²
v = dx/ dt = 2 (t – 3) = 0 ⇒ t = 3
x = (3 – 3)² ⇒ x = 0.
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- One solid sphere A and another hollow sphere B are of same mass and same outer radii.
- If a nucleus ᴢXᴬ emits 9α and 5β-particles, then the ratio of total protons and neutrons
- Initial angular velocity of a circular disc of mass M is ?￢ﾂﾁ.Then, two small spheres
- The energy band gap is maximum in
- The charge flowing through a resistance R varies with time t as Q=at-bt²,
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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