| ⇦ | 
| ⇨ |
The displacement ‘x’ (in meter) of a particle of mass ‘m’ (in kg) moving in one dimension under the action of a force, is related to time ‘t’ (in sec) by t = √x + 3. The displacement of the particle when its velocity is zero, will be
Options
(a) 2 m
(b) 4 m
(c) zero
(d) 6 m
Correct Answer:
zero
Explanation:
t = √x + 3
⇒ √x = t – 3 ⇒ x = (t – 3)²
v = dx/ dt = 2 (t – 3) = 0 ⇒ t = 3
x = (3 – 3)² ⇒ x = 0.
Related Questions: - A deutron is bombarded on ₈O¹⁶ nucleus and α-particle is emitted. The product nucleus is
- A rectangular copper coil is placed in a uniform magnetic field of induction 40 mT
- Two metallic spheres of radii 1 cm and 3 cm are given charges of -1 x 10⁻² C
- For non-conductors, the energy gap is
- Work of 3.0×10⁻⁴ joule is required to be done in increasing the size of a soap film
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A deutron is bombarded on ₈O¹⁶ nucleus and α-particle is emitted. The product nucleus is
- A rectangular copper coil is placed in a uniform magnetic field of induction 40 mT
- Two metallic spheres of radii 1 cm and 3 cm are given charges of -1 x 10⁻² C
- For non-conductors, the energy gap is
- Work of 3.0×10⁻⁴ joule is required to be done in increasing the size of a soap film
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply