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The displacement ‘x’ (in meter) of a particle of mass ‘m’ (in kg) moving in one dimension under the action of a force, is related to time ‘t’ (in sec) by t = √x + 3. The displacement of the particle when its velocity is zero, will be
Options
(a) 2 m
(b) 4 m
(c) zero
(d) 6 m
Correct Answer:
zero
Explanation:
t = √x + 3
⇒ √x = t – 3 ⇒ x = (t – 3)²
v = dx/ dt = 2 (t – 3) = 0 ⇒ t = 3
x = (3 – 3)² ⇒ x = 0.
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If we study the vibration of a pipe open at both ends
- The depth at which the effective value of acceleration due to gravity is g/4
- In Wheatstone bridge, three resistors P,Q and R are conncected in three arms
- A siren emitting sound of frequency 800 Hz is going away from a static listener
- The current in a conductor varies with time t as I=2t+3t² Where I is in amperes
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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