| ⇦ |
| ⇨ |
The dimensional formula for Young’s modulus is
Options
(a) [ML⁻¹T⁻²]
(b) [M⁰LT⁻²]
(c) [MLT⁻²]
(d) [ML²T⁻²]
Correct Answer:
[ML⁻¹T⁻²]
Explanation:
Young’s modulus Y=Stress/Strain=(Force/Area)/(elongation/Iength)
Y=[MLT⁻²][L]/[L²][L] = [ML⁻¹T⁻²]
Related Questions: - Pick out the correct statements from the following
- Mass and diameter of a ring is 2 kg and 1 m respectively. The moment of inertia
- A body of mass 10 kg is moving on an inclined plane of inclination 30°with an acceleration
- The dimensions of latent heat are
- Heat is flowing through a rod of length 50 cm and area of cross-section 5 cm².
Topics: Physical World and Measurement
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Pick out the correct statements from the following
- Mass and diameter of a ring is 2 kg and 1 m respectively. The moment of inertia
- A body of mass 10 kg is moving on an inclined plane of inclination 30°with an acceleration
- The dimensions of latent heat are
- Heat is flowing through a rod of length 50 cm and area of cross-section 5 cm².
Topics: Physical World and Measurement (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply