| ⇦ |
| ⇨ |
The dimension of 1/2ε₀E², where ε₀ is permittivity of free space and E is electric field, is:
Options
(a) ML²T⁻²
(b) ML⁻¹T⁻²
(c) ML²T⁻¹
(d) MLT⁻¹
Correct Answer:
ML⁻¹T⁻²
Explanation:
1/2 ?¬ツタE² represents energy density i.e., energy per unit volume.
⇒ [ 1/2 ?¬ツタE² ] = ML²T⁻² / L³
= ML⁻¹T⁻²
Related Questions: - At what height h above earth, the value of g becomes g/2 (where R=radius of earth)?
- In a diffraction pattern due to a singleslit of width a, the first minimum is observed
- which of the following statement is false for the properties of electromagnetic waves?
- A rod of 10 cm length is moving perpendicular to uniform magntic field of intensity
- A mass m moves in a circle on a smooth horizontal plane with velocity v₀
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Physical World and Measurement
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- At what height h above earth, the value of g becomes g/2 (where R=radius of earth)?
- In a diffraction pattern due to a singleslit of width a, the first minimum is observed
- which of the following statement is false for the properties of electromagnetic waves?
- A rod of 10 cm length is moving perpendicular to uniform magntic field of intensity
- A mass m moves in a circle on a smooth horizontal plane with velocity v₀
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Physical World and Measurement (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply