| ⇦ | 
| ⇨ |
The dimension of 1/2ε₀E², where ε₀ is permittivity of free space and E is electric field, is:
Options
(a) ML²T⁻²
(b) ML⁻¹T⁻²
(c) ML²T⁻¹
(d) MLT⁻¹
Correct Answer:
ML⁻¹T⁻²
Explanation:
1/2 ?￢ﾂﾀE² represents energy density i.e., energy per unit volume.
⇒ [ 1/2 ?￢ﾂﾀE² ] = ML²T⁻² / L³
= ML⁻¹T⁻²
Related Questions: - To measure the roughness of the surface of a material, which of the following microscope
- Avalanche breakdown is due to
- When a magnet is taken towards a coil, the induced e.m.f. depends on
- A soap bubble is charged to a potential 12V. If its radius is doubled,
- The de-Broglie wavelength of an electron is the same as that of a 50 KeV X-ray photon.
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Physical World and Measurement
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- To measure the roughness of the surface of a material, which of the following microscope
- Avalanche breakdown is due to
- When a magnet is taken towards a coil, the induced e.m.f. depends on
- A soap bubble is charged to a potential 12V. If its radius is doubled,
- The de-Broglie wavelength of an electron is the same as that of a 50 KeV X-ray photon.
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Physical World and Measurement (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply