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The binding energy per nucleon of ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06MeV, respectively. In the nuclear reaction ₃⁷Li+₁¹H→ ₂⁴He+ ₂⁴He+Q, the value of energy Q released is
Options
(a) 19.6 MeV
(b) (-24 MeV)
(c) 8.4 MeV
(d) 17.3 MeV
Correct Answer:
17.3 MeV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A charge of 100 μC has a potential at a distance of 9 m is
- The resistance of a bulb filament is 100 Ω at a temperature of 100⁰C.
- A beam of light of wavelength 590 nm is focussed by a converging lens of diameter
- A particle of mass m is projected with velocity v making an angle of 45° with
- A particle moving along X-axis has acceleration f,at time t given by f=fₒ(1- t/T)
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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