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The binding energy per nucleon of ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06MeV, respectively. In the nuclear reaction ₃⁷Li+₁¹H→ ₂⁴He+ ₂⁴He+Q, the value of energy Q released is
Options
(a) 19.6 MeV
(b) (-24 MeV)
(c) 8.4 MeV
(d) 17.3 MeV
Correct Answer:
17.3 MeV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A cricketer catches a ball of mass 150 g in 0.1 sec moving with speed 20 m/s
- Electrons of mass m with de-Broglie wavelength λ fall on the target in an X-ray tube.
- Calculate power output of ₉₂²³⁵U reactor, if it takes 30 days to use up 2 kg of fuel,
- Two point charge +9e and +e are at 16 cm away from each other.
- If the alternating current I=I₁ cosωt+I₂ sinωt, then the rms current is given by
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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