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The binding energy per nucleon of ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06MeV, respectively. In the nuclear reaction ₃⁷Li+₁¹H→ ₂⁴He+ ₂⁴He+Q, the value of energy Q released is
Options
(a) 19.6 MeV
(b) (-24 MeV)
(c) 8.4 MeV
(d) 17.3 MeV
Correct Answer:
17.3 MeV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two resistors of 6Ω and 9Ω are connected in series to a 120 V source.
- The ionisation energy of hydrogen is 13.6 eV. The energy of the photon released
- A body of mass m=3.513 kg is moving along the x-axis with a speed of 5 m/s
- The voltage gain of an amplifier with 9% negative feedback is 10. The voltage gain
- A ray of light is incident on a transparent glass slab of refractive index 1.62
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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