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The binding energy per nucleon of ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06MeV, respectively. In the nuclear reaction ₃⁷Li+₁¹H→ ₂⁴He+ ₂⁴He+Q, the value of energy Q released is
Options
(a) 19.6 MeV
(b) (-24 MeV)
(c) 8.4 MeV
(d) 17.3 MeV
Correct Answer:
17.3 MeV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The time of reverberation of a room A is one second. What will be the time (in seconds)
- What is the amount of energy released by deuterium and tritium fusion?
- A source and an observer approach each other with same velocity 50 m/s. If the frequency
- Two discs of moment of inertia I₁ and I₂ and angular speeds ?￢ﾂﾁ and ?￢ﾂﾂ are rotating
- A ball is dropped from a height of 20 cm. Ball rebounds to a height of 10cm
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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