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The binding energy per nucleon of ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06MeV, respectively. In the nuclear reaction ₃⁷Li+₁¹H→ ₂⁴He+ ₂⁴He+Q, the value of energy Q released is
Options
(a) 19.6 MeV
(b) (-24 MeV)
(c) 8.4 MeV
(d) 17.3 MeV
Correct Answer:
17.3 MeV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The potential energy of particle in a force field is U = A/r² – b/r, where A and B
- The frequency of fundamental tone in an open organ pipe of length
- A capacitor of 2.5 μF is charged through a resistor of 4 MΩ. In how much time
- A U²³⁵ reactor generates power at a rate of P producing 2×10⁸ fission per second.
- The radioactivity of a certain material drops to 1/16 of the initial value in 2 hours.
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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