| ⇦ | 
| ⇨ |
The binding energy per nucleon of ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06MeV, respectively. In the nuclear reaction ₃⁷Li+₁¹H→ ₂⁴He+ ₂⁴He+Q, the value of energy Q released is
Options
(a) 19.6 MeV
(b) (-24 MeV)
(c) 8.4 MeV
(d) 17.3 MeV
Correct Answer:
17.3 MeV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - In the Young’s double slit experiment, the intensity of light at a point on the screen
- Which one of the following statements is true, if half-life of a radioactive substance
- If the kinetic energy of the particle is increased to 16 times its previous value
- In an unbiased p-n junction, holes diffuse from the p-region to n-region because of
- On the horizontal surface of a truck a block of mass 1 kg is placed (µ=0.6) and truck
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In the Young’s double slit experiment, the intensity of light at a point on the screen
- Which one of the following statements is true, if half-life of a radioactive substance
- If the kinetic energy of the particle is increased to 16 times its previous value
- In an unbiased p-n junction, holes diffuse from the p-region to n-region because of
- On the horizontal surface of a truck a block of mass 1 kg is placed (µ=0.6) and truck
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply