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The binding energy per nucleon of ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06MeV, respectively. In the nuclear reaction ₃⁷Li+₁¹H→ ₂⁴He+ ₂⁴He+Q, the value of energy Q released is
Options
(a) 19.6 MeV
(b) (-24 MeV)
(c) 8.4 MeV
(d) 17.3 MeV
Correct Answer:
17.3 MeV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The manifestation of band structure in solids is due to
- A thin glass(refractive index 1.5) lens has optical power of -5D in air.
- A nucleus ᵐₙ X emits one α- particle and two β- particles. The resulting nucleus is
- A conductor of length 5 cm is moved parallel to itself with a speed of 2 m/s,
- A straight conductor of length 0.4 m is moved with a speed of 7 ms⁻¹perpendicular
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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