The average power dissipated in a pure inductor is

⇦

⇨

The average power dissipated in a pure inductor is

Options

(a) VI²/4
(b) 1/2 VI
(c) zero
(d) VI²

Correct Answer:

zero

Explanation:

In the inductor circuit, phase difference (ɸ) = 90° or π / 2

we know that, Pₐᵥ = V(rms) I(rms) cos ɸ = V(rms) I(rms) cos(π/2)

Therefore, Pₐᵥ = 0

Related Questions:

1. A body revolved around the sun 27 times faster than the earth. What is the ratio
2. Which radiations are used in tratement of muscles ache?
3. A potentiometer wire of length L and a resistance r are connected in series with
4. The Boolean expression P+ P ̅ Q, where P and Q are the inputs of the logic
5. A magnetic needle suspended parallel to a magnetic field requires √3J of work

Topics: Alternating Current (96)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends