| ⇦ |
| ⇨ |
The average power dissipated in a pure inductor is
Options
(a) VI²/4
(b) 1/2 VI
(c) zero
(d) VI²
Correct Answer:
zero
Explanation:
In the inductor circuit, phase difference (ɸ) = 90° or π / 2
we know that, Pₐᵥ = V(rms) I(rms) cos ɸ = V(rms) I(rms) cos(π/2)
Therefore, Pₐᵥ = 0
Related Questions: - On bombarding U²³⁵ by slow neutron, 200 MeV energy is released. If the power output
- The ratio of the dimensions of planck’s constant and that of the moment of inertia is
- Two liquid drops having diameters of 1 cm and 1.5 cm. The ratio of excess
- A tyre filled with air (27° C and 2 atm) bursts. The temperature of air is (ˠ=1.5)
- A layer of glycerine of thickness 1 mm present between a large surface area of 0.1 m².
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- On bombarding U²³⁵ by slow neutron, 200 MeV energy is released. If the power output
- The ratio of the dimensions of planck’s constant and that of the moment of inertia is
- Two liquid drops having diameters of 1 cm and 1.5 cm. The ratio of excess
- A tyre filled with air (27° C and 2 atm) bursts. The temperature of air is (ˠ=1.5)
- A layer of glycerine of thickness 1 mm present between a large surface area of 0.1 m².
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply