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The average power dissipated in a pure inductor is
Options
(a) VI²/4
(b) 1/2 VI
(c) zero
(d) VI²
Correct Answer:
zero
Explanation:
In the inductor circuit, phase difference (ɸ) = 90° or π / 2
we know that, Pₐᵥ = V(rms) I(rms) cos ɸ = V(rms) I(rms) cos(π/2)
Therefore, Pₐᵥ = 0
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Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An α-particle and a proton travel with the same velocity in a magnetic field
- In a series resonant LCR circuit, the voltage across R is 100 volts and R =1kΩ
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- Which component of electromagnetic spectrum have maximum wavelength?
- The e.m.f. of a battery is 2 V and its internal resistance is 0.5 Ω. The maximum
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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