| ⇦ | 
| ⇨ |
A force acts on a 3.0 g particle in such a way that the position of the particle as a function of time is given by x = 3t – 4t² + t³ , where x is in metre and t is in second. The work done during the first 4 s is
Options
(a) 570 mj
(b) 450 mj
(c) 490 mj
(d) 530 mj
Correct Answer:
530 mj
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The angular velocity of a wheel increases from 100 rps to 300 rps in 10 seconds.
- A cell can be balanced against 110 cm and 100 cm of potentiometer wire, respectively
- A uniform rod of length l is placed with one end in contact with the horizontal
- If a solid sphere of mass 1 kg and radius 0.1 m rolls without slipping at a uniform
- A particle starts its motion from rest under the action of a constant force
Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The angular velocity of a wheel increases from 100 rps to 300 rps in 10 seconds.
- A cell can be balanced against 110 cm and 100 cm of potentiometer wire, respectively
- A uniform rod of length l is placed with one end in contact with the horizontal
- If a solid sphere of mass 1 kg and radius 0.1 m rolls without slipping at a uniform
- A particle starts its motion from rest under the action of a constant force
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply