⇦ | ⇨ |
The angular speed of earth, so that the object on equator may appear weightless is(g = 10 m/s², radius of earth=6400 km)
Options
(a) 1.25 x 10⁻³ rad/s
(b) 1.56 x 10⁻³ rad/s
(c) 1.25 x 10⁻1 rad/s
(d) 1.56 rad/s
Correct Answer:
1.25 x 10⁻³ rad/s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A ballet dancer, dancing on smooth floor, is spinning about a vertical axis
- The energy required to charge a parallel plate condenser of plate separation d
- Two bullets are fired simultaneously, horizontally and with different speeds
- Two coils of self inductance 2 mH and 8 mH are placed so close together
- The de-Broglie wavelength of an electron moving with a velocity 1.5×10⁸ ms⁻¹ is equal
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A ballet dancer, dancing on smooth floor, is spinning about a vertical axis
- The energy required to charge a parallel plate condenser of plate separation d
- Two bullets are fired simultaneously, horizontally and with different speeds
- Two coils of self inductance 2 mH and 8 mH are placed so close together
- The de-Broglie wavelength of an electron moving with a velocity 1.5×10⁸ ms⁻¹ is equal
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Solution:
ω=√(g/R)=√(10/6400*10^3)=1.25*10^(-3) rad/s