| ⇦ | 
| ⇨ |
The angular speed of earth, so that the object on equator may appear weightless is(g = 10 m/s², radius of earth=6400 km)
Options
(a) 1.25 x 10⁻³ rad/s
(b) 1.56 x 10⁻³ rad/s
(c) 1.25 x 10⁻1 rad/s
(d) 1.56 rad/s
Correct Answer:
1.25 x 10⁻³ rad/s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - In radioactive element, β-rays are emitted from
- An interference pattern was made by using red light. If the red light
- The power obtained in a reactor using U²³⁵ disintegration is 1000 kW
- The drift speed of electrons in copper wire of diameter and length l is v.
- A mass m moves in a circle on a smooth horizontal plane with velocity v₀
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In radioactive element, β-rays are emitted from
- An interference pattern was made by using red light. If the red light
- The power obtained in a reactor using U²³⁵ disintegration is 1000 kW
- The drift speed of electrons in copper wire of diameter and length l is v.
- A mass m moves in a circle on a smooth horizontal plane with velocity v₀
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Solution:
ω=√(g/R)=√(10/6400*10^3)=1.25*10^(-3) rad/s