| ⇦ | 
| ⇨ |
The angular speed of earth, so that the object on equator may appear weightless is(g = 10 m/s², radius of earth=6400 km)
Options
(a) 1.25 x 10⁻³ rad/s
(b) 1.56 x 10⁻³ rad/s
(c) 1.25 x 10⁻1 rad/s
(d) 1.56 rad/s
Correct Answer:
1.25 x 10⁻³ rad/s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The mirrors are inclined at an angle of 50⁰. The number of images formed for an object
- Which one of the following statements is true, if half-life of a radioactive substance
- A circular disc of radius R is removed from a bigger circular disc of radius 2R
- If by mistake voltmeter is connected in series and ammeter in parallel then
- If the momentum of electron is changed by P, then the de-Broglie wavelength
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The mirrors are inclined at an angle of 50⁰. The number of images formed for an object
- Which one of the following statements is true, if half-life of a radioactive substance
- A circular disc of radius R is removed from a bigger circular disc of radius 2R
- If by mistake voltmeter is connected in series and ammeter in parallel then
- If the momentum of electron is changed by P, then the de-Broglie wavelength
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Solution:
ω=√(g/R)=√(10/6400*10^3)=1.25*10^(-3) rad/s