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The angular speed of earth, so that the object on equator may appear weightless is(g = 10 m/s², radius of earth=6400 km)
Options
(a) 1.25 x 10⁻³ rad/s
(b) 1.56 x 10⁻³ rad/s
(c) 1.25 x 10⁻1 rad/s
(d) 1.56 rad/s
Correct Answer:
1.25 x 10⁻³ rad/s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An electron revolves in a circle at the rate of 10¹⁹ rounds per second.
- In nuclear fusion, two nuclei come together to form a large nucleus.
- A particle is dropped vertically from rest, from a height.The time taken by it to fall
- Dimensional formula for electrical resistance R is given by
- A radioactive sample S₁ having an activity of 5 μCi has twice the number of nuclei
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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Solution:
ω=√(g/R)=√(10/6400*10^3)=1.25*10^(-3) rad/s