| ⇦ | 
| ⇨ |
The angular speed of earth, so that the object on equator may appear weightless is(g = 10 m/s², radius of earth=6400 km)
Options
(a) 1.25 x 10⁻³ rad/s
(b) 1.56 x 10⁻³ rad/s
(c) 1.25 x 10⁻1 rad/s
(d) 1.56 rad/s
Correct Answer:
1.25 x 10⁻³ rad/s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - If |A x B|= √3 A.B , then the value of |A + B| is
- The length of an elastic string is a metre when the longitudinal tension is 4N and b
- Two parallel long wires carry currents i₁ and i₂ with i₁ > i₂ .
- In India, electricity is supplied for domestic use at 200V. It is supplied at 110 V
- Two masses of 9 g and 6 g are connected with a string which is passing over a frictionless
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If |A x B|= √3 A.B , then the value of |A + B| is
- The length of an elastic string is a metre when the longitudinal tension is 4N and b
- Two parallel long wires carry currents i₁ and i₂ with i₁ > i₂ .
- In India, electricity is supplied for domestic use at 200V. It is supplied at 110 V
- Two masses of 9 g and 6 g are connected with a string which is passing over a frictionless
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Solution:
ω=√(g/R)=√(10/6400*10^3)=1.25*10^(-3) rad/s