| ⇦ | 
| ⇨ |
The angular speed of earth, so that the object on equator may appear weightless is(g = 10 m/s², radius of earth=6400 km)
Options
(a) 1.25 x 10⁻³ rad/s
(b) 1.56 x 10⁻³ rad/s
(c) 1.25 x 10⁻1 rad/s
(d) 1.56 rad/s
Correct Answer:
1.25 x 10⁻³ rad/s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Which of the following phenomena support the wave theory of light?
- A coil of inductive reactance 31 Ω has a resistance of 8 Ω. It is placed in series
- Two charges each equal to 2µ C are 0.5m apart. If both of them exist inside vacuum
- Graph of force per unit length between two long parallel current carrying
- A body of mass 3 kg acted upon by a constant force is displaced by S meter
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following phenomena support the wave theory of light?
- A coil of inductive reactance 31 Ω has a resistance of 8 Ω. It is placed in series
- Two charges each equal to 2µ C are 0.5m apart. If both of them exist inside vacuum
- Graph of force per unit length between two long parallel current carrying
- A body of mass 3 kg acted upon by a constant force is displaced by S meter
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Solution:
ω=√(g/R)=√(10/6400*10^3)=1.25*10^(-3) rad/s