| ⇦ |
| ⇨ |
A circular disc of radius R is removed from a bigger circular disc of radius 2R such that the circumferences of the discs coincide. The centre of mass of the new disc is α/R from the centre of the bigger disc. The value of α is
Options
(a) -1/4
(b) -1/3
(c) -1/2
(d) -1/6
Correct Answer:
-1/3
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - There is a ring of radius r having linear charge densityλ and rotating with a uniform
- A change of 0.04 V takes place between the base and the emitter when an input
- An electron in a circular orbit of radius 0.05 nm performs 10¹⁶ rev/s. The magnetic
- When a radioactive substance emits an ∝ particle, its position in the periodic table
- Assuming the sun to have a spherical outer surface of radius r
Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- There is a ring of radius r having linear charge densityλ and rotating with a uniform
- A change of 0.04 V takes place between the base and the emitter when an input
- An electron in a circular orbit of radius 0.05 nm performs 10¹⁶ rev/s. The magnetic
- When a radioactive substance emits an ∝ particle, its position in the periodic table
- Assuming the sun to have a spherical outer surface of radius r
Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply