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The angular speed of earth, so that the object on equator may appear weightless is(g = 10 m/s², radius of earth=6400 km)
Options
(a) 1.25 x 10⁻³ rad/s
(b) 1.56 x 10⁻³ rad/s
(c) 1.25 x 10⁻1 rad/s
(d) 1.56 rad/s
Correct Answer:
1.25 x 10⁻³ rad/s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- α-particles, deuterons and protons of same energy are moving in a perpendicular
- An ideal heat engine works between temperature T₁=500 K and T₂=375 K.
- A copper disc of radius 0.1 m is rotated about its centre, with 10 revolutions
- The electron of a hydrogen atom revolves round the proton in a circular
- The magnetic field at the centre of a circular coil carrying current I ampere is B.
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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Solution:
ω=√(g/R)=√(10/6400*10^3)=1.25*10^(-3) rad/s