| ⇦ | 
| ⇨ |
The amount of copper deposited by one Faraday current will be maximum in an acidic solution of one litre of
Options
(a) 1 M Cu₂Cl₂
(b) 2 M Cu(NO₃)₂
(c) 5 M CuSO₄
(d) 5 M Cu₃(PO₄)₂
Correct Answer:
1 M Cu₂Cl₂
Explanation:
In 1 M Cu₂Cl₂. Cu⁺ (one faraday = 96500C) deposited = 63.5 g of Cu. In 2 M Cu(NO₃)₂. Cu²⁺ (2F = 2⨯96500C) deposited 63.5 of Cu. Therefore 1F deposited 63.5/2 g of Cu. In 5 M CuF₂. Cu²⁺ (2F = 2⨯96500 C) deposited 63.5 g of Cu. Therefore 1F = 96500 C deposited 63.5/2 g of Cu. so Cu deposited by 1 Faraday will be maximum in case of 1M Cu₂Cl₂.
Related Questions: - Salol is an
- When enthalpy and entropy change for a chemical reaction are – 2.5 x 10³ cals
- Aqueous solution of which of the following compounds is the best conductor
- Ethyl alcohol gives ethyl chloride with the help of
- In which of the solutions containing following solutes, its normality is equal
Topics: Electrochemistry and Chemical Kinetics
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Salol is an
- When enthalpy and entropy change for a chemical reaction are – 2.5 x 10³ cals
- Aqueous solution of which of the following compounds is the best conductor
- Ethyl alcohol gives ethyl chloride with the help of
- In which of the solutions containing following solutes, its normality is equal
Topics: Electrochemistry and Chemical Kinetics (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply