| ⇦ | 
| ⇨ |
A solution of nickel sulphate in which nickel rod is dipped is diluted 10 times. the reduction potential of Ni at 298 K
Options
(a) decreases by 60 mV
(b) decreases by 30 mV
(c) decreases by 30 V
(d) increases by 30 mV
Correct Answer:
decreases by 30 mV
Explanation:
Let the initial concentration of Ni²⁺ = a. Since the solution is diluted 10 times, its concentration = a/10. Applying Nernst equation, E = E⁰ – 0.0591/2 log a /a/10. E = E⁰ – 0.030(log 10) ⇒ E = E⁰ – 0.030. Therefore the reduction potential of Ni decreases by 30 mV.
Related Questions: - The long form of periodic table is based on
- The enthalphy change for the reaction N₂ + 3H₂ → 2NH₃ is -92.38 kJ at 298K
- Which one among the following contains a phenolic -OH group
- Which one of the following acids would you expect to be the strongest
- Bauxite is concentrated by
Topics: Electrochemistry and Chemical Kinetics
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The long form of periodic table is based on
- The enthalphy change for the reaction N₂ + 3H₂ → 2NH₃ is -92.38 kJ at 298K
- Which one among the following contains a phenolic -OH group
- Which one of the following acids would you expect to be the strongest
- Bauxite is concentrated by
Topics: Electrochemistry and Chemical Kinetics (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply