The acceleration of an electron in an electric field of magnitude 50 V/cm,

⇦

⇨

The acceleration of an electron in an electric field of magnitude 50 V/cm, if e/m value of the electron is 1.76×10¹¹ C/kg will be

Options

(a) 8.8×10¹⁴ m/sec²
(b) 3×10¹³ m/sec²
(c) 5.4×10¹² m/sec²
(d) Zero

Correct Answer:

8.8×10¹⁴ m/sec²

Explanation:

Acceleration = a = eE / m

⇒ a = 1.76 × 10¹¹ × 50 × 10 ¹²

⇒ a = 8.8 × 10 ¹⁴ m/ sec²

Related Questions:

1. Which one of the following statement is FALSE ?
2. A body under the action of a force F⃗ = 6i⃗–8j⃗+10k⃗, acquires an accelerationof 1 m/s². The mass of this body must be
3. When the energy of the incident radiation is increased by 20%,
4. An inclined plane makes an angle of 30° with the horizontal.A solid sphere
5. A source is moving towards an observer with a speed of 20 m/s and having frequency

Topics: Electrostatics (146)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends