| ⇦ | 
| ⇨ |
Electric field intensity at a point in between two parallel sheets due to like charges of same surface charge densities (σ) is
Options
(a) σ/2ε₀
(b) σ/ε₀
(c) Zero
(d) 2σ/ε₀
Correct Answer:
Zero
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Two wires of the same dimensions but resistivities p1 and p2 are connected in series
- Two point white dots are 1 mm apart on a black paper.
- If a vector 2i+3j+8k is perpendicular to the vector 4j-4i+αk, then value of α is
- The drive shaft of an automobile rotates at 3600 rpm and transmits 80 HP
- A silver wire of radius 0.1 cm carries a current of 2A. If the charge density in silver
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two wires of the same dimensions but resistivities p1 and p2 are connected in series
- Two point white dots are 1 mm apart on a black paper.
- If a vector 2i+3j+8k is perpendicular to the vector 4j-4i+αk, then value of α is
- The drive shaft of an automobile rotates at 3600 rpm and transmits 80 HP
- A silver wire of radius 0.1 cm carries a current of 2A. If the charge density in silver
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply