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The acceleration due to gravity becomes (g/2) where g=acceleration due to gravity on the surface of the earth at a height equal to
Options
(a) 4R
(b) R/4
(c) 2R
(d) R/2
Correct Answer:
R/4
Explanation:
Acceleration due to gravity g=GM/R² Acceleration due to gravity on the surface of the height is g’ = GM/(R+h)² .·. g/g’ = (GM/R²)/(GM/(R+h)²) = (R+h/R)² = (1+h/R)² g’/g = (1+h/R)⁻² = (1-2h/R), When h<<R (g/2)/g = (1-2h/R) ⇒ 1/2 = (1-2h/R) ⇒ 2h/R = 11/2 ⇒ 2h/R = 1/2 ⇒ h = (1/2)(R/2) = R/4
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In Young’s double silt experiment, 12 fringes are observed to be formed
- Potential at a point x-distance from the centre inside the conducting sphere
- The r.m.s speed of the molecules of a gas in a vessel is 400 m/s
- A 70 kg man stands in contact against the inner wall of a hollow cylindrical drum
- A stone falls freely under gravity. It covers distances h1, h2 and h3 in the first 5 secs
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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